2x^2-22x-22=2

Solution for 2x^2-22x-22=2 equation:

Simplifying
2x2 + -22x + -22 = 2

Reorder the terms:
-22 + -22x + 2x2 = 2

Solving
-22 + -22x + 2x2 = 2

Solving for variable 'x'.

Reorder the terms:
-22 + -2 + -22x + 2x2 = 2 + -2

Combine like terms: -22 + -2 = -24
-24 + -22x + 2x2 = 2 + -2

Combine like terms: 2 + -2 = 0
-24 + -22x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-12 + -11x + x2) = 0

Factor a trinomial.
2((-1 + -1x)(12 + -1x)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-1 + -1x)' equal to zero and attempt to solve:

Simplifying
-1 + -1x = 0

Solving
-1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1x = 0 + 1
-1x = 0 + 1

Combine like terms: 0 + 1 = 1
-1x = 1

Divide each side by '-1'.
x = -1

Simplifying
x = -1
Subproblem 2
Set the factor '(12 + -1x)' equal to zero and attempt to solve:

Simplifying
12 + -1x = 0

Solving
12 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1x = 0 + -12
-1x = 0 + -12

Combine like terms: 0 + -12 = -12
-1x = -12

Divide each side by '-1'.
x = 12

Simplifying
x = 12
Solution
x = {-1, 12}